Lottery Odds Explained

How lottery odds are calculated: counting combinations, comparing games and reading the numbers. For readers aged 18 and over.

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About the guide

Odds Atlas is an independent educational guide to the mathematics of lottery draws in the United States. It explains probability, prizes and payouts. It does not sell tickets and does not promise wins.

Explore the topics

Probability

Combinations, odds versus probability and how common lottery formats compare.

Choosing numbers

Are draws random, quick pick or your own numbers, and how syndicates work.

Jackpots and prizes

How prize pools are funded, lump sum versus annuity, and what scratch-off odds include.

How lottery odds are calculated

Lottery odds begin with the number of distinct outcomes a draw can produce. For a standard six-number draw, the calculation depends on how many numbers are available and how many are selected. Factorials provide a compact way to count those possible sets without listing them individually. Once the total is known, a single ticket’s chance can be expressed as a fraction, a percentage or a one-in-N figure.

Counting combinations

A lottery combination is a set of selected numbers in which order is irrelevant. If the draw selects 6 numbers from 49, a ticket containing 4, 12, 19, 27, 33 and 46 matches the same set regardless of the order in which those numbers are drawn. A permutation counts different orders as separate outcomes; a combination counts that set just once. The combination formula is C(n,k) = n! / (k!(n-k)!), where n is the total number available, k is the number selected and the exclamation mark denotes a factorial. For 6 numbers from 49, substitute n = 49 and k = 6, then cancel the factorial terms:

  1. Set n to 49 and k to 6: C(49,6) counts the distinct six-number sets available from the 49 numbers.
  2. Write the factorial form as 49! / (6! × 43!), because 49 minus 6 leaves 43 unselected numbers.
  3. Cancel 43! from the numerator and denominator, leaving 49 × 48 × 47 × 46 × 45 × 44 divided by 6!.
  4. Evaluate 6! as 6 × 5 × 4 × 3 × 2 × 1, which equals 720 and removes the repeated ordering of each set.
  5. Calculate 49 × 48 × 47 × 46 × 45 × 44 / 720 = 13,983,816 possible six-number combinations.

The division by 720 matters because each group of six distinct numbers can be arranged in 720 different orders, but all those arrangements represent one lottery result. Counting permutations without dividing would count the same ticket set repeatedly. With 13,983,816 equally possible combinations and one selected set on a ticket, that ticket has a probability of 1 / 13,983,816 of matching all six numbers.

Odds versus probability

Probability describes the share of all possible outcomes that meet a specified condition. When one outcome among N is successful, the probability is 1/N; as a percentage, multiply that fraction by 100. In everyday lottery language, “1 in N” expresses the same chance: one winning combination among N equally likely combinations. It does not mean a win is due after N attempts, because each draw is a separate event. For a 6 of 49 draw, the count is 13,983,816 combinations, so one ticket has a 1 in 13,983,816 chance of matching all six numbers. The corresponding probability is 1 / 13,983,816, or about 0.000007 percent. The percentage is tiny because the favorable outcome is one part of a set containing nearly 14 million possibilities. In formal mathematical usage, odds compare favorable outcomes with unfavorable ones, rather than expressing a probability as a fraction of all outcomes. Here, the odds against a jackpot match are 13,983,815 to 1: there is one favorable combination and 13,983,815 others. Lottery explanations often use “odds of 1 in 13,983,816” as shorthand for the probability, so checking whether a figure refers to probability or formal odds avoids confusing those two formats.

Why every combination is equally likely

Equal chances rely on a fair draw: each eligible number must have the same chance of selection, and the draw must not favor particular number sets. Since the ticket matches a set rather than a sequence, the order of the six drawn numbers does not create additional outcomes.

  • In a properly conducted draw of six distinct numbers from 49, every six-number set is one of the 13,983,816 possible combinations.
  • The draw order does not change a set: 3-8-14-22-37-49 represents the same combination in any sequence.
  • The combination 1-2-3-4-5-6 is exactly as likely as any other, including a set that appears less orderly.
  • Numbers described as “hot” or “cold” do not make a particular combination more or less likely in a fair, independent draw.
  • It is not true that the outcome is “win or lose, so 50 percent”; one favorable set among 13,983,816 is not an even chance.

A pattern that looks unusual to a person still has the same probability as any other specified set under these assumptions. The odds come from counting, not from luck or pattern.

Abstract probability charts and distribution curves

Odds of common lottery formats

Lottery formats differ in the number of values available in each pool and in how many values a ticket must match. A six-number selection from one pool has a different combination count from a format that also requires a bonus number. When the bonus comes from a separate pool, each main selection can be paired with every eligible bonus value. The examples below compare the resulting jackpot chances for three generic formats.

A 6 of 49 game

In a 6 of 49 game, a ticket selects six numbers from 49, and the jackpot requires matching the six drawn numbers. The combination count is 49 choose 6: 49! ÷ (6! × 43!) = 13,983,816. A single ticket therefore has jackpot odds of 1 in 13,983,816.

The pool size sets the number of available six-number combinations: each valid set is one possible jackpot match. For a fixed selection of six, increasing the number of numbers in the pool adds possible sets, so the chance attached to one ticket becomes smaller. The order in which the six numbers are listed does not create additional sets; a ticket with the same six values is still the same combination.

Ten different tickets cover ten combinations, giving jackpot odds of about 1 in 1.4 million. That is a larger coverage than one ticket provides, but it remains a small share of the 13,983,816 possible sets. The practical takeaway is that the 49-number pool, together with the requirement to match six numbers, determines the one-ticket odds.

A 6 of 59 game

A 6 of 59 game has 45,057,474 possible six-number combinations. A ticket covering one of those combinations has jackpot odds of 1 in 45,057,474. The six selected numbers must match the six required numbers; the larger pool does not change how many numbers a ticket contains.

Compared with a 6 of 49 format, the pool contains ten additional numbers while the selection remains six. Those extra choices create many more possible six-number sets: the 6 of 59 count is about 3.22 times as large. As a result, a single ticket corresponds to a smaller fraction of all jackpot combinations.

This illustrates the effect of changing the initial pool while keeping the selection size fixed. The odds are not determined by the number six alone; the total pool matters as well. For a reader comparing formats, the useful figure is the total combination count and its one-ticket equivalent: here, 1 in 45,057,474.

A game with a bonus number pool

A separate bonus pool adds another requirement to the jackpot match. In a format that selects five numbers from 69 and one bonus number from 26, first count the possible five-number main selections: 11,238,513. Each of those selections can be paired with any of the 26 bonus numbers, so the total is 11,238,513 × 26 = 292,201,338 combinations. One ticket has jackpot odds of 1 in 292,201,338.

The multiplication matters because every main-number set has 26 possible bonus-number partners. The bonus pool does not add 26 to the main combination count; it multiplies that count by 26. A jackpot ticket must match both parts of the result, so the relevant total includes every main-set and bonus-number pairing.

The table compares the one-ticket jackpot odds for the three formats. Each odds figure uses the total number of combinations for that format.

Jackpot combinations and one-ticket odds by format
FormatHow it is builtCombinationsOdds as 1 in N
6 of 49Choose 6 from 4913,983,8161 in 13,983,816
6 of 59Choose 6 from 5945,057,4741 in 45,057,474
5 from 69 plus 1 from 26Choose 5 from 69, then 1 bonus number from 2611,238,513 × 26 = 292,201,3381 in 292,201,338

The comparison shows how a second pool can substantially expand the total number of jackpot outcomes. The 5-from-69 plus 1-from-26 format has more possible combinations than either single-pool format because every eligible main selection must also be matched with a specific bonus number.

What the odds mean in practice

A probability becomes easier to judge when it is translated into a ticket count or a familiar everyday comparison. The examples below show how buying additional entries affects your chance of matching a jackpot combination, and how a number in the millions compares with repeated coin flips. The calculations use a 6-of-49 jackpot with 13,983,816 possible combinations. They illustrate why a percentage can rise while the overall chance remains small.

Buying more tickets

With distinct tickets, each added combination covers one more possible jackpot result, so the chance rises almost linearly: n distinct entries cover n out of 13,983,816 combinations. The examples below put that increase into percentages and distinguish distinct entries from an independent-draw model.

  • One distinct ticket covers 1 of 13,983,816 combinations, giving a jackpot chance of about 0.00000715 percent.
  • 1,000 different tickets cover 1,000 combinations and give about 0.007 percent, still far below one chance in ten thousand.
  • Buying 100,000 distinct combinations gives a chance of about 0.715 percent, because 100,000 divided by 13,983,816 is approximately 0.00715.
  • One million distinct combinations cover about 7.15 percent of the possible results; the increase tracks the fraction of combinations entered.
  • For distinct entries, the exact 50 percent point is 6,991,908 tickets, half of 13,983,816 possible combinations.
  • The formula n = ln(0.5) / ln(1 – 1/N) gives about 9.69 million for a 50 percent chance when ticket outcomes are modeled as independent selections.

The formula’s 9.69 million result allows for selections that could repeat a combination. If every ticket must be different, repeats are excluded and 6,991,908 entries cover exactly half the combinations. This distinction matters when interpreting the standard independent-selection formula and when estimating lottery winning chances.

Even millions of tickets do not make a 6-of-49 jackpot a realistic certainty: 9.69 million independent selections correspond to only a 50 percent chance, not a guarantee. The practical conclusion is that no realistic number of tickets changes the picture.

A scale for very large numbers

The number 13,983,816 can be compared with the outcomes of repeated fair coin flips. Each flip has two possible results, so the number of possible sequences after k flips is 2k. After 23 flips there are 223, or 8,388,608, sequences; after 24 there are 224, or 16,777,216. The combination count sits between those two totals.

More precisely, 13,983,816 is about 223.7. A fractional flip is a mathematical comparison rather than a literal coin-toss experiment, but it gives a useful scale: the chance of getting heads on every one of about 23.7 fair flips is roughly one in 13,983,816. For a whole-number illustration, 24 heads in a row has a probability of 1 in 16,777,216, a little less likely than one result among 13,983,816.

This analogy does not mean that lottery draws work like coin flips; it translates a large count into a sequence most people can picture. Getting heads repeatedly sounds unlikely because each flip adds another factor of one-half. The same compounding makes a jackpot-sized number feel distant even before it is written as a percentage.

For readers trying to understand lottery odds, the useful takeaway is the scale, not a prediction: a jackpot combination is comparable to an uninterrupted run of roughly 24 successful coin flips. Adding a modest number of tickets cannot bridge that gap. No realistic number of tickets changes the picture, even though every extra distinct combination increases the chance by a measurable amount.

Questions about lottery odds

These answers clarify how ticket chances relate to draw results, prize size, and repeated play; gamble only if you meet the legal age where you live, and keep play within responsible limits.

Are lottery odds the same for every ticket?

Yes: the odds for one ticket do not depend on the jackpot size or on results from past draws. In a fair game, each draw is independent, so a previous result cannot make a particular combination more or less likely next time. The rules also set a fixed number of possible combinations for that game. Each ticket represents one combination, and that count does not change because some numbers have appeared often or have not appeared recently. A rollover may change the advertised prize, but not the probability attached to one ticket.

What is the difference between odds and probability?

Probability is the share of outcomes that win, while odds compare winning outcomes with losing ones; lottery chances are often presented informally as “1 in N.” For example, if one of four equally likely outcomes wins, the probability is 1/4, or 25%. The odds in favour are 1:3 because there is one winning outcome for every three losing outcomes; the odds against are 3:1. Probability uses all outcomes in its denominator, whereas odds compare the two outcome groups directly.

Do odds change when the jackpot grows?

No: a growing jackpot does not improve or reduce the probability that one ticket wins it. The prize amount can rise as money rolls over, but the draw still uses the same rules and possible combinations. For a game with jackpot odds of 1 in 13,983,816, that figure remains 1 in 13,983,816 when the advertised prize grows. The jackpot changes what a winning ticket may pay, not the likelihood of matching the winning combination in that draw.

Does buying the same numbers every week change the odds?

No: playing the same numbers each week does not change their odds in any individual draw. Each fair draw is an independent trial, with no memory of the numbers selected or results from earlier weeks. If your chosen combination misses, it does not become “due” to win; if it wins, that result does not make it more likely to win again. Keeping the numbers consistent may make your selection routine predictable, but it does not alter the draw’s probability calculation.